按名称获取Lua函数参考。

2015-10-7 9:23:19
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我想通过函数名字符串查找函数的参考:

function someFunc(a) print(a*2) end

-- 我想做这样的事情（我知道这行不通）
ref = _G ['someFunc']

someFunc 在我的脚本被调用之前声明为全局函数。

我知道简单的方法是这样做:

ref = someFunc

...但这不是我想要的。我需要通过字符串查找函数。

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用户1095108
用户1095108

你一定做错了什么：

Lua 5.3.1  Copyright (C) 1994-2015 Lua.org, PUC-Rio
> function someFunc(a) print(a*2) end
> for key,value in pairs(_G) do print(key,value) end
type    function: 0x1b8c280
rawget  function: 0x41bc70
rawlen  function: 0x41bcc0
tonumber        function: 0x41b990
_VERSION        Lua 5.3
_G      table: 0x1b8a9f0
coroutine       table: 0x1b8a7e0
load    function: 0x41c3b0
select  function: 0x41b890
debug   table: 0x1b8cf60
getmetatable    function: 0x41c530
next    function: 0x41beb0
setmetatable    function: 0x41c170
collectgarbage  function: 0x41c0a0
unpack  function: 0x424f10
print   function: 0x41bd50
ipairs  function: 0x41c300
bit32   table: 0x1b909f0
error   function: 0x41c030
loadfile        function: 0x41c4c0
arg     table: 0x1b90e80
xpcall  function: 0x41b770
tostring        function: 0x41b860
pairs   function: 0x41c2e0
rawset  function: 0x41bc20
utf8    table: 0x1b90180
require function: 0x1b8a720
math    table: 0x1b8f2d0
rawequal        function: 0x41bd10
someFunc        function: 0x1bb0160
io      table: 0x1b8d5c0
assert  function: 0x41c600
package table: 0x1b8c4a0
pcall   function: 0x41b800
loadstring      function: 0x41c3b0
module  function: 0x1b8c450
table   table: 0x1b8d2c0
string  table: 0x1b8be70
os      table: 0x1b8d040
dofile  function: 0x41c580
> _G["someFunc"]
function: 0x1bb0160
> _G['someFunc']
function: 0x1bb0160
2015-10-07 10:17:42

作者:

用户365929

用户365929
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