在尝试将语法重新组织为两个文件时出现异常的ANTLR错误。

我将我的语法重新组织为两个文件，以适应树状语法：Lua.g和LuaGrammar.g。Lua.g将包含所有的词法规则，LuaGrammar.g将包含所有的树形语法和解析规则。但是，当我尝试编译LuaGrammar.g时，我会得到以下错误：

[00:28:37] error(10):  internal error: C:\Users\RCIX\Desktop\AguaLua\Project\trunk\AguaLua\AguaLua\ANTLR Data\LuaGrammar.g : java.lang.IllegalArgumentException: Can't find template ruleRefBang.st; group hierarchy is [CSharp2]
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:507)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:484)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.stringtemplate.StringTemplateGroup.lookupTemplate(StringTemplateGroup.java:484)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:392)
org.antlr.stringtemplate.StringTemplateGroup.getInstanceOf(StringTemplateGroup.java:404)
org.antlr.grammar.v2.CodeGenTreeWalker.getRuleElementST(CodeGenTreeWalker.java:152)
org.antlr.grammar.v2.CodeGenTreeWalker.atom(CodeGenTreeWalker.java:1986)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1708)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1556)
org.antlr.grammar.v2.CodeGenTreeWalker.alternative(CodeGenTreeWalker.java:1306)
org.antlr.grammar.v2.CodeGenTreeWalker.block(CodeGenTreeWalker.java:1081)
org.antlr.grammar.v2.CodeGenTreeWalker.ebnf(CodeGenTreeWalker.java:1871)
org.antlr.grammar.v2.CodeGenTreeWalker.element(CodeGenTreeWalker.java:1704)
org.antlr.grammar.v2.CodeGenTreeWalker.alternative(CodeGenTreeWalker.java:1306)
org.antlr.grammar.v2.CodeGenTreeWalker.block(CodeGenTreeWalker.java:1081)
org.antlr.grammar.v2.CodeGenTreeWalker.rule(CodeGenTreeWalker.java:797)
org.antlr.grammar.v2.CodeGenTreeWalker.rules(CodeGenTreeWalker.java:588)
org.antlr.grammar.v2.CodeGenTreeWalker.grammarSpec(CodeGenTreeWalker.java:530)
org.antlr.grammar.v2.CodeGenTreeWalker.grammar(CodeGenTreeWalker.java:336)
org.antlr.codegen.CodeGenerator.genRecognizer(CodeGenerator.java:432)
org.antlr.Tool.generateRecognizer(Tool.java:641)
org.antlr.Tool.process(Tool.java:454)
org.antlr.works.generate.CodeGenerate.generate(CodeGenerate.java:104)
org.antlr.works.generate.CodeGenerate.run(CodeGenerate.java:185)
java.lang.Thread.run(Unknown Source)

并且，当尝试生成Lua.g时，我得到以下错误：

[00:34:58] error(100): C:\Users\RCIX\Desktop\AguaLua\Project\trunk\AguaLua\AguaLua\ANTLR Data\Lua.g:0:0: syntax error: codegen: <AST>:0:0: unexpected end of subtree

为什么会出现这些错误，我该如何修复它们？（使用ANTLR V3，可以提供语法文件）

更新：这是我尝试编译的语法文件。

``` 树形语法LuaGrammar;

选项{ 回溯=true; 语言=CSharp2; 输出=AST; TokenVocab=Lua; 过滤器=真; ASTLabelType=CommonTree; }

分配 : ^('=' left=NAME right=NAME) {Ast. }; /*

chunk : (stat (';'!)?)* (laststat (';'!)?)?;

块 : 块;

stat : varlist1 '='^ explist1 | functioncall | doblock | 'while'^ exp doblock | 'repeat'^ block untilrule | 'if'^ exp thenchunk elseifchunk* elsechunk? 'end'! | 'for'^ forinitializer doblock | 'for'^ namelist inlist doblock | 'function'^ funcname funcbody | 'local' 'function' NAME funcbody | 'local'^ namelist localstat? ;

localstat : '='^ explist1;

untilrule : 'until'^ exp;

elseifchunk : 'elseif'^ exp thenchunk;

thenchunk : 'then'^ block;

elsechunk : 'else'^ block;

forinitializer : NAME '='^ exp ','! exp (','! exp)?;

doblock : 'do'^ block 'end'!;

inlist : 'in'^ explist1;

laststat : 'return'^ (explist1)? | 'break';

dotname : '.'! funcname;

colonname : ':' NAME;

funcname : NAME^ (dotname | colonname)?;

varlist1 : var (','! var)*;

namelist : NAME (','! NAME)*;

explist1 : (exp ','!)* exp; */