lua打开一个包含表格的文件并更改特定值
2020-10-8 10:50:53
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我有一个包含大量表格的文件。需要打开它,获取某些值并用新值替换其他值。在这个例子中,Females和Males Classroom a和b必须等于Teachers Classroom a和b。 阅读了许多有关IO的内容,但我似乎无法正确地使其工作。任何帮助将不胜感激。
--用于测试的示例数据文件,原始文件有7000多行
theData =
{
["theSchool"] =
{
["theTeachers"] =
{
["theClassroom"] =
{
["a"] = 001,
["b"] = 002,
},
},
["theFemales"] =
{
["theClassroom"] =
{
["a"] = 005,
["b"] = 010,
},
},
["theMales"] =
{
["theClassroom"] =
{
["a"] = 012,
["b"] = 014,
},
},
},
}
然后文件函数就像这样
local file = io.open(filepath,'r')
local newCa = '["a"] = '..theData.theSchool.theTeachers.theClassroom.a
local newCb = '["b"] = '..theData.theSchool.theTeachers.theClassroom.b
local replaceFa = '["a"] = '..tostring(theData.theSchool.theFemales.theClassroom.a)
local replaceFb = '["b"] = '..tostring(theData.theSchool.theFemales.theClassroom.b)
local replaceMa = '["a"] = '..tostring(theData.theSchool.theMales.theClassroom.a)
local replaceMb = '["b"] = '..tostring(theData.theSchool.theMales.theClassroom.b)
file:close()
--它会工作吗?
print("原始值:")
print(newCa)
print(newCb)
print(replaceFa)
print(replaceFb)
print(replaceMa)
print(replaceMb)
file = io.open(filepath,'r+')
function lines_from(filepath)
lines = {}
for line in io.lines(filepath) do
lines[#lines + 1] = line
end
return lines
end
local lines = lines_from(filepath)
for k,v in ipairs(lines) do
if v == replaceFa then
file:write(newCa..'\n')
elseif v == replaceFb then
file:write(newCb..'\n')
elseif v == replaceMa then
file:write(newCa..'\n')
elseif v == replaceMb then
file:write(newCb..'\n')
else
file:write(v..'\n')
end
--('[' .. k .. ']', v)
end
--replaceF = {[a] = newCa, [b] = newCb}
--replaceM = {[a] = newCa, [b] = newCb}
--file:write(replaceF)
--file:write(replaceM)
--print(tostring(theData.theSchool.theFemales.theClassroom.a))
file:close()
file = io.open(filepath,'r')
--它是否起作用?
print("新值:")
print(theData.theSchool.theTeachers.theClassroom.a)
print(theData.theSchool.theTeachers.theClassroom.b)
print(theData.theSchool.theFemales.theClassroom.a)
print(theData.theSchool.theFemales.theClassroom.b)
print(theData.theSchool.theMales.theClassroom.a)
print(theData.theSchool.theMales.theClassroom.b)```
> 在它起作用后,我会删除所有打印信息。
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尝试这个方案,一次性读取文件中的表格将更快,并且一次性写入也更好用。
--- 读取 local handle = io.open("data.lua",'rb') local data = handle:read("*a") handle:close() data = data .. "\n return theData" local t = loadstring(data)() -- 编辑 theData.theSchool.theTeachers.theClassroom.a = theData.theSchool.theTeachers.theClassroom.a + 1 -- 写入 local function concat(t, r) r = r or {} for k,v in pairs(t) do if type(v)=="table" then r[#r+1] = string.format('\t["%s"]={\n',k ) concat(v, r) r[#r+1] = "\t},\n" else r[#r+1] = string.format('\t\t["%s"]=%03s,\n',k ,v ) end end return r end local r = concat(t) local text = "theData = { \n " .. table.concat(r) .. "}" print(text) -- 只是控制 local handle = io.open("data.lua",'wb') local data = handle:write(text) handle:close()