Lua 中将时间取到 5 分钟的间隔

2020-7-13 11:12:48

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我有一个字符串变量，需要将它四舍五入到 5 分钟的间隔，但保持为字符串。例如： 12:23am 应该变成 12:25am 12:58pm 应该变成 01:00pm 11:59am 应该变成 12:00pm。我在 Lua 中尝试过，但效果并不好，我相信有更好的方法来做到这一点。也许有人可以指导我或提供帮助。这是我做的事情：

startRoundH = string.sub(var, 1, 2)
startRoundM1 = string.sub(var, 4, 4)
startRoundM2 = string.sub(var, 5, 5)
startAMPM = string.lower(string.sub(var, 6, 7))
if tonumber(startRoundM2) <= 2 then
    startRoundM2 = "0"
elif tonumber(startRoundM2) > 2 and tonumber(startRoundM2) <= 7 then
    startRoundM2 = "5"
elif tonumber(startRoundM2) == 8 or tonumber(startRoundM2) == 9 then
    startRoundM2 = "0"
    if tonumber(startRoundM1) ~= 5 then
        startRoundM1 = tonumber(startRoundM1) + 1
    else
        startRoundM1 = "0"
        if tonumber(startRoundH) < 9 then
            startRoundH = tonumber(startRoundH) + 1 startRoundH = "0" .. startRoundH
        elseif tonumber(startRoundH) == 10 or tonumber(startRoundH) == 9 then
            startRoundH = tonumber(startRoundH) + 1
        elseif tonumber(startRoundH) == 11 then
            startRoundH = "12"
            if startAMPM == "am" then
                startAMPM = "pm"
            else
                startAMPM = "am"
            end
        elseif tonumber(startRoundH) == 12 then
            startRoundH = "01"
        end
    end
end

谢谢！

用户1847592

local function round5min(var)
   local h, m, ampm = var:match"^(%d+):(%d+)(%a+)$"
   local t = (({am=0,pm=12})[ampm:lower()]+h%12)*60+m+2
   t = t-t%5
   m = t%60
   t = (t-m)/60
   h = t%12
   return ("%d:%02d%s"):format((h-1)%12+1, m, ({"am","pm"})[(t-h)/12%2+1])
end

print(round5min("9:23am"))   --> 9:25am
print(round5min("11:56am"))  --> 11:55am
print(round5min("11:57am"))  --> 11:55am
print(round5min("11:58am"))  --> 12:00pm
print(round5min("11:59am"))  --> 12:00pm
print(round5min("11:59pm"))  --> 12:00am

这是一个Lua函数，用于将给定时间向上或向下调整到接近5分钟的整点。函数的输入是一个字符串，格式为HH:MMam（上午）或HH:MMpm（下午），输出为相同格式的时间字符串。

该函数的实现非常精巧。它首先从输入字符串中解析出小时、分钟和am / pm标记，并将它们转换为总分钟数。然后，它将分钟数向下舍入到最接近5分钟的倍数，并将总分钟数转换回小时和分钟。最后，它使用Lua的字符串格式化功能将调整后的时间转换回字符串格式。

该函数的输出结果如下：

print(round5min("9:23am"))   --> 9:25am
print(round5min("11:56am"))  --> 11:55am
print(round5min("11:57am"))  --> 11:55am
print(round5min("11:58am"))  --> 12:00pm
print(round5min("11:59am"))  --> 12:00pm
print(round5min("11:59pm"))  --> 12:00am

2020-07-13 12:49:51

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作者:

用户88888888

Lua 中将时间取到 5 分钟的间隔

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