如何获取括号中的字符串（多个字）

你可以使用 %b pattern 来指定你想匹配的括号：

str = "Reason = Failed to connect ( Nickname: Mc Gee ), Banned by: Andrew"
print(str:match("%b()"):gsub("[()]","")) -- 输出 ` Nickname: Mc Gee `

有一个复杂的回答：

local str = "Reason = Failed to connect ( Nickname: Mc Gee ), Banned by: Andrew"
print(string.match(str, "Reason = [%a%s]+%([%a%s]+:%s+(.*)%s+%).*"))
-- Mc Gee

希望它有用~

str = "Reason = Failed to connect ( Nickname: Mc Gee ), Banned by: Andrew"
print(str:match("%((.-)%)"))

也就是说：

str = "失败原因 = 无法连接 (昵称:麦基), 被禁止连接的人: 安德鲁"
print(str:match("%((.-)%)"))