Lua：如何将字符串反序列化为多维表？

Nifim's答案非常完美，我的问题已经解决了。

可以使用以下代码读取表格：

loadstring(serializedTable)()

再次感谢！

你的表格可能包含字符串，其中包含字符串"，换行符，制表符等。我为自己编写了此函数来处理：

local function buildLiteral(value, tableAsVararg, buildedLiteralsCache)
    if not buildedLiteralsCache then
        buildedLiteralsCache = {}
    end

    local resultStr = nil

    if value == nil then
        resultStr = "nil"
    else
        if not buildedLiteralsCache[value] then
            local t = type(value)
            local str = nil

            if t == "boolean" or t == "number" then
                str = tostring(value)
            elseif t == "string" then
                str = "\"" .. string.gsub(string.gsub(string.gsub(string.gsub(string.gsub(value, "\\", "\\\\"), "\"", "\\\""), "\r", "\\r"), "\n", "\\n"), "\t", "\\t") .. "\""
            elseif t == "table" then
                if tableAsVararg then
                    str = ""

                    if table.getn(value) >= 1 then
                        for _, v in ipairs(value) do
                            str = str .. buildLiteral(v, false, buildedLiteralsCache) .. ", "
                        end

                        str = string.sub(str, 1, string.len(str) - 2)
                    end
                else
                    str = "{"

                    for k, v in pairs(value) do
                        str = str .. "[" .. buildLiteral(k, false, buildedLiteralsCache) .. "]=" .. buildLiteral(v, false, buildedLiteralsCache) .. ", "
                    end

                    if string.len(str) > 1 then
                        str = string.sub(str, 1, string.len(str) - 2)
                    end

                    str = str .. "}"
                end
            else
                error("buildLiteral called with unsupported type='" .. t .. "'")
            end

            buildedLiteralsCache[value] = str
        end

        resultStr = buildedLiteralsCache[value]
    end

    return resultStr
end

您可以使用loadstring(str)()再次加载表格。