获得表格中值的最佳优化方法

我需要检查第一个值是否大于等于 'from'，第二个值是否小于等于 'to'，如果是，则我的函数返回数字。它能够工作，但我不知道这是否是获得表格中值的最佳且最优化的方式。

local table = {
    {from = -1, to = 12483, number = 0},
    {from = 12484, to = 31211, number = 1},
    {from = 31212, to = 53057, number = 2},
    {from = 53058, to = 90200, number = 3},
    {from = 90201, to = 153341, number = 4},
    {from = 153342, to = 443162, number = 5},
    {from = 443163, to = 753380, number = 6},
    {from = 753381, to = 1280747, number = 7},
    {from = 1280748, to = 2689570, number = 8},
    {from = 2689571, to = 6723927, number = 9},
    {from = 6723928, to = 6723928, number = 10}
}

local exampleFromValue = 31244
local exampleToValue = 42057

local function getNumber()
    local number = 0
    for k, v in pairs(table) do
        if (v.from and exampleFromValue >= v.from) and (v.to and exampleToValue <= v.to) then
            number = v.number
            break
        end
    end

    return number
end

print(getNumber())