Lua - 判断时间是否在两个时间戳之间

给出以下示例：

--测试   当前     开始     结束     是否在两者之间
--1     10:00    09:00    12:00   true
--2     01:00    07:34    09:54   false
--3     17:00    16:00    03:00   true
--4     10:00    10:00    15:00   true
--5     10:30    10:00    10:30   true

在 Lua 中，如何创建一个可以调用的函数：

BetweenTimes("10:00", "09:00","12:00")

在这种情况下（测试1）返回 true。我遇到的问题是测试用例3。

我可以假设第一个时间永远在第二个时间之前。

我想这可能就是它：

local function parse_time(str)
   local hour, min = str:match("(%d+):(%d+)")
   return os.time{hour = hour, min = min, day = 1, month = 1, year = 1970}
end

local function BetweenTimes(between, start, stop)
   between = parse_time(between)
   start   = parse_time(start)
   stop    = parse_time(stop)

   if stop < start then
      return (start <= between) or (between <= stop)
   else
      return (start <= between) and (between <= stop)
   end
end

print(BetweenTimes("10:00", "09:00", "12:00")) -- true
print(BetweenTimes("15:00", "09:00", "12:00")) -- false
print(BetweenTimes("15:00", "09:00", "01:00")) -- true
print(BetweenTimes("10:00", "10:00", "11:00")) -- true
print(BetweenTimes("11:00", "10:00", "11:00")) -- true
print(BetweenTimes("19:00", "17:00", "03:30")) -- true
print(BetweenTimes("03:00", "04:00", "05:30")) -- false
print(BetweenTimes("03:00", "02:00", "05:30")) -- true
print(BetweenTimes("01:00", "09:00", "02:30")) -- true

或者只需使用以下代码即可删除 os.time()：

local function BetweenTimes(between, start, stop)
   local start   = string.gsub(start,":", "")
   local between = string.gsub(between,":", "")
   local stop    = string.gsub(stop,":", "")

   if stop < start then
      return (start <= between) or (between <= stop)
   else
      return (start <= between) and (between <= stop)
   end
end