如何在函数内部访问或更改本地变量在其外部？

您可以使用_G表变量来存储和检索您真正需要存储和检索的“全局”变量。或者更好的方法是创建自己的自定义模块。

下面的代码未经测试：

tuning.lua

M.TUNING_VAR = {}

-- just an example
local helloWorld = function()
   print("Hello World!")
end
M.template_path = '/BASEMODULE_PATH/file.tmpl'
function M:TUNING()
  return self.TUNING_VAR
end
function M:SET_TURNING(tbl)
 if tbl == nil then
        tbl = {}
 end
 self.TURNING = tbl
end
function M:Tune(overrides)
    if overrides == nil then
        overrides = {}
    end
    --以下是游戏中使用的本地变量
    local seg_time = 30
    local total_day_time = seg_time*16

    local day_segs = 10
    local dusk_segs = 4
    local night_segs = 2

    --默认白天的组成。在冬天等季节发生变化
    local day_time = seg_time * day_segs
    local dusk_time = seg_time * dusk_segs
    local night_time = seg_time * night_segs

    local multiplayer_attack_modifier = 1
    local multiplayer_goldentool_modifier = 1
    local multiplayer_armor_durability_modifier = 0.7
    local multiplayer_armor_absorption_modifier = 1
    local multiplayer_wildlife_respawn_modifier = 1

    local wilson_attack = 34 * multiplayer_attack_modifier
    local wilson_health = 150
    local calories_per_day = 75

    local wilson_attack_period = .1
    -----------------------

    local perish_warp = 1--/200
    --your code

    self:SET_TURNING(overrides) -- or whatever your want
end

M.helloWorld = helloWorld
return M

用法

the_other_lua_file.lua

local module = require "turning"
module:TURNING()["yourwantedvariable"] = newvalue